Magellan’s expedition made a trip around the world in 3 years, and in 89 minutes Gagarin circled the globe. The paths traversed by them are approximately equal. How many times the average flight speed of Yuri Gagarin exceeded the average speed of Magellan’s expedition?
First, we remember that the distance covered by the expedition and Yuri Alekseevich Gagarin are approximately the same. To compare the average speeds, we must use the formula: υg / υm υg = s / 89 min; υm = s / 3 · 365 · 24 · 60min In order to answer the question of the task, we take the ratio of average speeds and get: υg / υm = 3 · 365 · 24 · 60 min / 89min = 17716.85 times.
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