# Merged two solutions of sulfuric acid: 120 g 40% and 180 g 10%. Find the mass fraction of acid in the resulting solution. Given: m1 (solution) = 120 g,: ω1 (acid) = 40%, or 0.4, m2 (solution) = 180 g,: ω2 (acid) = 10%, or 0.1.
Find: ω (acid) -?
Decision.
1. Find the mass of the solute (acid) in the first solution:
m1 (acid) = m1 (solution) • ω1 (acid) = 120 g • 0.4 = 48 g.
2. Find the mass of the solute (acid) in the second solution:
m2 (acid) = m2 (solution) • ω2 (acid) = 180 g • 0.1 = 18 g.
3. Find the mass of the solute in the resulting solution:
m (acid) = m1 (acid) + m2 (acid) = 48 g + 18 g = 66 g.
4. Find the mass of the resulting solution:
m (solution) = m1 (solution) + m2 (solution) = 120 g + 180 g = 300 g.
5. Find the mass fraction of the dissolved substance (acid) in the resulting solution:
ω (acid) = m (acid) / m (solution) = 66 g: 300 g = 0.22, or 22%. Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.