On a straight conductor 20 cm long, located perpendicular to the direction of the magnetic field, a force of 8 N acts. Determine the value of the magnetic induction vector if the current in the conductor is 40 A.
Given: L = 20cm = 0.2m; F = 8H; I = 40A. Find: vector B
Solution: vector B = F / L * I. B = 8H \ 0.2m * 40A = 1T
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