On heating 69 g of ethanol with concentrated sulfuric acid used as a catalyst, several compounds were formed, one of which completely

On heating 69 g of ethanol with concentrated sulfuric acid used as a catalyst, several compounds were formed, one of which completely reacts with 120 g of a 40% solution of bromine with carbon tetrachloride. The second compound is a flammable liquid. Determine the mass of compounds formed during heating of ethanol, assuming that the alcohol has completely reacted.

C2H5OH – (H2SO4) → C2H4 + H2O
C2H4 + Br2 – (CCl4) → C2H4Br2
2C2H5OH – (H2SO4) → C2H5OC2H5 + H2O
m (pure bromine) = 120 x 0.4 = 48 g
n (Br2) = 48/160 = 0.3 mol
⇒ n (C2H4) = 0.3 mol
m (C2H4) = 0.3 x (24 + 4) = 8.4 g
m (C2H5OH in the first reaction) = 0.3 x (25 + 5 + 17) = 13.8 g
m (C2H5OH in the second reaction) = 69 – 13.8 = 55.2 g
n (C2H5OH in the second reaction) = 55.2 / 46 = 1.2 mol
⇒ n (С4Н10O) = 1.2: 2 = 0.6 mol
m (C4H10O) = 0.6 x (24 + 24 + 10 + 16) = 44.4 g
Answer: the mass of ethylene is 8.4 g, the mass of dimethyl ether is 44.4 g.

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