One of the air masses has a temperature of 0оС and an absolute humidity of 4.5 g / m3, the second air mass has a temperature
One of the air masses has a temperature of 0оС and an absolute humidity of 4.5 g / m3, the second air mass has a temperature of + 15оС and an absolute humidity of 9.6 g / m3. Determine in which of the air masses and how many times the relative humidity is greater.
1) According to the table, we determine that at a temperature of 0оС Q = 5 g / m3, at a temperature of + 15оС Q = 13 g / m3
2) Determine the relative humidity of the first air mass:
r = q: Q × 100% = 4.5 g / m3: 5 g / m3 × 100% = 90%
3) Determine the relative humidity of the second air mass:
r = q: Q × 100% = 9.6 g / m3: 13 g / m3 × 100% = 74%
4) 90%: 74% = 1.2 times – the relative humidity of the first air mass is higher.
Answer: the relative humidity of the first air mass is 1.2 times higher.
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