# Point D on side AB of triangle ABC is chosen so that AD = AC. It is known that ∠CAB = 19 ° and ∠ACB = 160 °. Find the angle of the DCB.

May 31, 2020 | Education

| Consider the triangle ACD.

By the theorem on the sum of the angles of a triangle:

180 ° = ∠CAB + ∠ADC + ∠ACD

180 ° = 19 ° + ∠ADC + ∠ACD

∠ADC + ∠ACD = 161 °

Since AD = AC, this triangle is isosceles.

Then, ∠ADC = ∠ACD (by the property of an isosceles triangle), we obtain that:

∠ADC = ∠ACD = 161 ° / 2 = 80.5 °

∠DCB = ∠ACB-∠ACD = 160 ° -80.5 ° = 79.5 °

Answer: 79.5

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