Point H is the base of the height BH drawn from the vertex of the right angle B of the right triangle ABC. A circle with diameter BH intersects sides AB and CB at points P and K, respectively. Find PK if BH = 16
∠KBP = 90 ° (by condition)
A right triangle KPB with hypotenuse PK is inscribed in a circle.
Therefore, PK is the diameter of the circle. (by the circumscribed circle theorem).
KP = BH = 16
Answer: PK = 16
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