# Technical soda ash containing 5% impurities was treated with an excess of hydrochloric acid. In this case, 2 mol of carbon dioxide

Technical soda ash containing 5% impurities was treated with an excess of hydrochloric acid. In this case, 2 mol of carbon dioxide were released. Determine the mass of technical soda that has reacted with the acid. 1) Let’s compose the reaction equation:
Na2CO3 + 2HCl = NaCl + CO2 ↑ + H2O
2) Calculate the mass of pure Na2CO3:
According to the reaction equation:
n (Na2CO3) = n (CO2) = 2 mol
m (Na2CO3) = n (Na2CO3) ∙ M (Na2CO3) = 2 ∙ 106 = 212 g.
3) Determine the mass of technical soda:
ω (Na2CO3) = 100 – ω (impurities) = 100-5 = 95%
m (mineral) = m (Na2CO3) ∙ 100% / ω (Na2CO3) = 212 ∙ 100/95 = 223.16 g. Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.