Technical soda ash containing 5% impurities was treated with an excess of hydrochloric acid. In this case, 2 mol of carbon dioxide

Technical soda ash containing 5% impurities was treated with an excess of hydrochloric acid. In this case, 2 mol of carbon dioxide were released. Determine the mass of technical soda that has reacted with the acid.

1) Let’s compose the reaction equation:
Na2CO3 + 2HCl = NaCl + CO2 ↑ + H2O
2) Calculate the mass of pure Na2CO3:
According to the reaction equation:
n (Na2CO3) = n (CO2) = 2 mol
m (Na2CO3) = n (Na2CO3) ∙ M (Na2CO3) = 2 ∙ 106 = 212 g.
3) Determine the mass of technical soda:
ω (Na2CO3) = 100 – ω (impurities) = 100-5 = 95%
m (mineral) = m (Na2CO3) ∙ 100% / ω (Na2CO3) = 212 ∙ 100/95 = 223.16 g.
Answer: 223.16 g

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