The amount of formaldehyde required to obtain 1 liter of formalin (p = 1.11 g / ml) with a mass fraction of formaldehyde of 10% is

Formalin is a formaldehyde solution.
Determine the mass of the solution
m = V * p
m = 1000ml * 1.11g / ml = 1110g
Determine the mass of the substance in solution.
m substance = ω * m solution
m substance = 0.1 * 1110 = 111g
Determine the volume of the substance V = Vm * n, n = m / M
V = Vm * m / M
V = 82.88 L
Write down the number to the nearest tenth.
The answer is 82.9 liters

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