The amount of oxygen required to completely burn 1.6 g of methane

bystudin | May 28, 2020 | Education

CH4 + 2O2 = CO2 + 2H2O
2n (CH4) = n (O2)
2m (CH4) / M (CH4) = V (O2) / 22.4
2 · 1.6 / 16 = V (O2) / 22.4
V (O2) = 4.48 L

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