The area of the right triangle is 968√3. One of the acute angles is 60 °. Find the length of the leg adjacent to this corner

The area of a right triangle is half the product of the legs:
S = AC * BC / 2 = 968√3
Let the angle BAC be equal to 60 degrees.
Tangent BAC:
td∠BAC = tg60 ° = BC / AC = √3 (according to the table).
BC = AC√3
S = AC * BC / 2 = 968√3
AC * BC = 1936√3
AC * AC√3 = 1936√3
AC2 = 1936
AC = 44
Answer: 44