The boiling liquid received from the heater an amount of heat equal to 200 kJ at normal atmospheric pressure.
| August 25, 2020 | Education
The boiling liquid received from the heater an amount of heat equal to 200 kJ at normal atmospheric pressure. The mass of the formed steam is 0.4 kg. What is the specific heat of vaporization of this liquid?
L = Q / m = 200,000 / 0.4 = 5 * 10 ^ 5 J / kg
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