The capacitor charge is 0.4 mC, the voltage between the plates is 500 V.The energy of the capacitor’s electric field is
August 5, 2020 | Education
| decision
Energy W = q * U / 2 = 0.4 * 10-3 * 500/2 = 0.1 J

decision
Energy W = q * U / 2 = 0.4 * 10-3 * 500/2 = 0.1 J