The catalytic hydrogenation of 1,3-butadiene gave a mixture of butane and isomeric butenes in a 1: 1 volume ratio.

The catalytic hydrogenation of 1,3-butadiene gave a mixture of butane and isomeric butenes in a 1: 1 volume ratio. What amount (mol) of butane is contained in the resulting mixture if it is known that the mixture discolored 320 g of bromine dissolved in chloroform?

2C4H6 + 3H2 → C4H10 + C4H8
C4H8 + Br2 → C4H8Br2
n (Br2) = 320/160 = 2 mol
n (C4H8) = n (Br2) = n (C4H10) = 2 mol
Answer: the resulting mixture contains 2 moles of butane.

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