The coin is thrown 4 times. Find the probability that the emblem will fall out 2 to 3 times

We write down all possible combinations for 4 coin tosses. To test ourselves, we immediately calculate that they should turn out n = 16! Here they are:
OOOO, OOOP, OOPO, OOPP, OPOO, OPOP, OPPO, OPPP,
POOO, POOP, POPO, POPP, PPOO, PPOP, PPPO, PPPP.
Now select those where the eagle occurs 2 or 3 times: OOOP, OOPO, OOPP, OPOO, OPOP, OPPO, POOO, POOP, POPO, PPOO,
there will be m = 10. Then the probability is P = m / n = 10/16 = 5/8 = 0.625

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