The content of nucleotides in the m-RNA chain is as follows: 34% guanine, 18% uracil, 28% cytosine, 20% adenine.

The content of nucleotides in the m-RNA chain is as follows: 34% guanine, 18% uracil, 28% cytosine, 20% adenine. Determine the percentage of nitrogenous bases in the DNA region that is the template for this m-RNA.

Obviously, 34% of guanine in i-RNA in the counted DNA strand will constitute 34% of cytosine, respectively, 18% of uracil – 18% of adenine, 28% of cytosine – 28% of guanine, 20% of adenine – 20% of thymine (according to the principle of complementarity of nucleotide bases ). In total, A + T and G + C in the calculated chain will be:
A + T = 18% + 20% = 38%; G + C = 28% + 34% = 62%.
In an uncoded strand (DNA is a double-stranded molecule), the total indicators will be the same, only the percentage of individual bases will be the opposite:
A + T = 20% + 18% = 38%; G + C = 34% + 28% = 62%.
In both chains, the pairs of complementary bases will be equally divided, i.e. adenine and thymine – 19% each, guanine and cytosine – 31% each.

Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.