The density of the hydrocarbon at standard equal to 1.964 g / l. The mass fraction of carbon in it is 81.82%.

The density of the hydrocarbon at standard equal to 1.964 g / l. The mass fraction of carbon in it is 81.82%. Derive the molecular formula for this hydrocarbon.

Mr = ρ x Vm = 1.964 x 22.4 = 44 g / mol
12n / 44 = 0.8182
⇔ n = 3
⇒ C3H8
Answer: the molecular formula of the hydrocarbon is C3H8.

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