The heat engine performs work of 100 J. per cycle. What amount of heat is received from the heater, if the efficiency of the engine is 20%?

work A = Qn-Qx (1)
Efficiency ή = (Qн-Qх) / Qн (2)
substitute (1) in (2)
ή = А / Qн
Qн = A / ή = 100 J / 0.20 = 500 J

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