The leg and hypotenuse of a right triangle are 15 and 39. Find the height drawn to the hypotenuse

AB – hypotenuse, BC – cathetus.
We find AC by the Pythagorean theorem:
AB2 = BC2 + CA2
39 ^ 2 = 15 ^ 2 + CA ^ 2
1521 = 225 + CA ^ 2
1296 = CA ^ 2
CA = 36
For triangle ABC:
sinA = CB / AB = 15/39 = 5/13
For triangle ACD:
sinA = CD / AC => CD = AC * sinA = 36 * 5/13 = 180/13 = 13 integers and 11/13
Answer: CD = 13 integers and 11/13

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