The mass of gas released during the treatment with an excess of hydrochloric acid 3 mol of sodium sulfide is equal to

Na2S 2HCl = 2 NaCl + H2S
Determine the amount of hydrogen sulfide released by the reaction equation
3/1 = X / 1
X = 3 mol (H2S)
Find the mass of hydrogen sulfide m = M * n
n = 34 g / mol * 3 mol = 102 g.

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