The mass of oxygen required for the complete combustion of 67.2 liters of hydrogen sulfide to SO2 is

It is necessary to compose the reaction equation 2H2S + 3O2 = 2SO2 + 2H2O. Calculate the amount of hydrogen sulfide substance 67.2 / 22.4 = 3 mol. It is possible to correlate by any method the amount of substance according to the equation and by the condition of the problem between hydrogen sulfide and oxygen. It turns out that the required amount of oxygen is 4.5 mol, because between them the ratio is 2 to 3. According to the reaction equation, calculate the mass of oxygen m = M * n (amount of substance). M = 32 g / mol (according to the periodic table). Therefore, m = 32 g / mol * 4.5 mol = 144 g.