The mass of salt formed during the dissolution of copper (II) oxide with a mass of 10 g in excess of sulfuric acid is

Compose a reaction equation
CuO + H2SO4 = CuSO4 + H2O
Calculate the amount of substance of copper oxide (CuO) 10 g / 80 g / mol = 0.125 mol
Calculate the amount of salt substance (CuSO4) = 0.125 mol (equal to the amount of copper oxide substance)
Calculate the salt mass m (CuSO4) = M * n (amount of substance) = 160 g / mol * 0.125 mol = 20 g

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