The mass of salt formed during the dissolution of iron (III) oxide weighing 40 g in excess of nitric acid is
Compose a reaction equation
Fe2O3 + 6HNO3 = 2Fe (NO3) 3 + 3H2O
Calculate the amount of substance of iron oxide (3) 40g / 160g / mol = 0.25 mol
Calculate the amount of salt substance (Fe (NO3) 3) = 0.25 * 2 = 0.5 mol
Calculate the mass of salt (Fe (NO3) 3) m = M * n (amount of substance) m = 0.5 mol * 242g / mol = 121g
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