The mass of salt formed during the dissolution of iron (III) oxide with a mass of 80 g in excess of nitric acid is

Compose a reaction equation
Fe2O3 + 6HNO3 = 2Fe (NO3) 3 + 3H2O
Calculate the amount of substance of iron oxide (3) n = 80g / 160g / mol = 0.5 mol
Calculate the amount of salt substance n (Fe (NO3) 3) = 0.5 * 2 = 1 mol
Calculate salt mass m (Fe (NO3) 3)
m = M * n (amount of substance)
m = 1 mol * 242g / mol = 242g

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