The mass of the precipitate formed by mixing a solution containing 34 g of silver nitrate and an excess of sodium chloride solution is
n (silver nitrate) = m / M = 34/170 = 0.2 mol
the number of moles of silver nitrate = the number of moles of silver chloride, which means
m (silver chloride) = M (silver chloride) * n (silver nitrate) = 28.7 g
Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.