The mass of the radioactive isotope of silver in 810 days decreased by 8 times. Determine the half-life of this isotope.

m = m 0 * 2 power (-t / T)
m0 / m = 2 power (t / T)
8 = 2 cubed = 2 power (810 / T)
3 = 810 / T
T = 810/3 = 270 days

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