The relative density of the vapors of the organic compound in terms of sulfur dioxide is 2. When 19.2 g of this substance are burned, 52.8

The relative density of the vapors of the organic compound in terms of sulfur dioxide is 2. When 19.2 g of this substance are burned, 52.8 g of carbon dioxide and 21.6 g of water are formed. Derive the molecular formula of an organic compound.

Solution: Mr / (32 + 32) = 2 ⇔ Mr = 2×64 = 128 g / mol
CxHy + O2 = CO2 + H2O
n (CO2) = 52.8 / 44 = 1.2 mol
n (H2O) = 21.6 / 18 = 1.2 mol
n (org. substances) = 19.2 / 128 = 0.15 mol ⇒ 1.2 / 0.15 = 8
C8H16O = 8×12 + 16 + 16 = 128 g / mol
Answer: the molecular formula of an organic compound is C8H16O.

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