The skater, rotating on the tip of the skate, spreads his arms to the sides to slow down his rotation. In this case, the moment of inertia of the skater relative to the axis of rotation changes n times. Knowing that the frictional forces acting on the skater are small enough, evaluate how the skater’s angular speed of rotation changes.
Since friction is negligible, the skater’s angular momentum must be preserved:
l1w1 = l2w2
Since the moment of inertia will increase n times, then the angular velocity of rotation will decrease n times.
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