The temperature of the air, which quickly rises at a speed of 5 cm / s for 7.5 hours, dropped by 13.5 ° C. Determine how many degrees the air temperature dropped when it was raised for every 100 m?
1) Determine the rate of air rise per hour:
5 cm / s × 3600 s = 18000 cm / h = 180 m / h
2) Determine the height to which the air rose in 7.5 hours:
180 m / hour × 7.5 hours = 1350 m
3) Δt = 13.5 ° C: 1350 m = 0.01 ° C / m = 1 ° C / 100 m
Answer: the air temperature dropped by 1 ° C for every 100 m of rise.
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