The volume of gas released during the dissolution of 22 g of iron (II) sulfide in an excess of sulfuric acid is

Compose a reaction equation
FeS + H2SO4 = H2S + FeSO4
Calculate the amount of substance of iron sulfide (2) (FeS) 22 g / 88 g / mol = 0.25 mol
Calculate the amount of gas substance (H2S) = 0.25 mol (equal to the amount of substance of iron sulfide)
Calculate the gas volume V (H2S) = Vm * n (amount of substance) = 22.4 l / mol * 0.25 mol = 5.6

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