The volume of gas released during the dissolution of 44 g of iron (II) sulfide in excess of hydrochloric acid is

bystudin | May 28, 2020 | Education

FeS + 2HCl = FeCl2 + H2S
Determine the amount of iron sulfide substance n = m / M, n = 44g / 88g / mol = 0.5 mol
Substitute the resulting figure in the equation and make up the proportion
0.5 / 1 = X / 1
x = 0.5 mol (H2S)
Find the gas volume V = Vm * n
V = 22.4 * 0.5 = 11.2 liters.

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