The woman’s father is hemophilic, and her husband is healthy. How likely is this woman to have a hemophilic son? The woman herself has normal blood coagulation.
A woman with normal blood coagulation, her genotype is XHXh. The woman’s father is hemophilic, which means that his genotype is XhY. Gamete Xh woman receives from him. The woman’s husband is healthy, his XHY genotype.
We make a crossbreeding pattern: P (women) XHXh → (husband) XHY.
A woman forms two types of gametes: XH; Xh.
A man forms two types of gametes: XH; Y.
Possible genotypes and phenotypes of children:
XHXH is a girl with normal blood coagulation.
XHY is a boy with normal blood coagulation.
XHXh is a girl with normal blood coagulation (carrier).
XhY is a hemophilic boy.
The probability of having a hemophilic son is 25%.
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