Two solutions were mixed: 33.3 g of calcium chloride and a sufficient amount of sodium phosphate. Calculate the mass of the sediment
| November 13, 2020 | Education
| Sequence of actions | Registration of the problem solution |
| 1. We write down the condition of the problem | Given:
m (CaCl2) = 33.3 g Find: m (Ca3 (PO4) 2) =? |
| 2. Let’s calculate the molar masses for the formulas written in the given | M (CaCl2) = 111 g / mol
M (Ca3 (PO4) 2) = 310 g / mol |
| 3. Let’s calculate the amount of substances, the mass of which is given in the condition | ν (CaCl2) = m / M = 33.3 g / 111 g / mol = 0.3 mol |
| 4. Let’s write down UHR. Let’s arrange the coefficients.
Under the formulas, we write the stoichiometric ratios displayed by the reaction equation. |
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| 5. Let’s calculate the amount of substance, the mass of which needs to be found | |
| 6. Let’s calculate the required mass | m (Ca3 (PO4) 2) = ν (Ca3 (PO4) 2 ∙ M (Ca3 (PO4) 2) = 0.1 mol ∙ 310 g / mol = 31 g |
| 7. Let’s write down the answer | Answer: m (Ca3 (PO4) 2) = 31 g |
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