Two solutions were mixed: 33.3 g of calcium chloride and a sufficient amount of sodium phosphate. Calculate the mass of the sediment
November 13, 2020
|Sequence of actions
||Registration of the problem solution
|1. We write down the condition of the problem
m (CaCl2) = 33.3 g
Find: m (Ca3 (PO4) 2) =?
|2. Let’s calculate the molar masses for the formulas written in the given
||M (CaCl2) = 111 g / mol
M (Ca3 (PO4) 2) = 310 g / mol
|3. Let’s calculate the amount of substances, the mass of which is given in the condition
||ν (CaCl2) = m / M = 33.3 g / 111 g / mol = 0.3 mol
|4. Let’s write down UHR. Let’s arrange the coefficients.
Under the formulas, we write the stoichiometric ratios displayed by the reaction equation.
|5. Let’s calculate the amount of substance, the mass of which needs to be found
|6. Let’s calculate the required mass
||m (Ca3 (PO4) 2) = ν (Ca3 (PO4) 2 ∙ M (Ca3 (PO4) 2) = 0.1 mol ∙ 310 g / mol = 31 g
|7. Let’s write down the answer
||Answer: m (Ca3 (PO4) 2) = 31 g
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