Two solutions were mixed: 33.3 g of calcium chloride and a sufficient amount of sodium phosphate. Calculate the mass of the sediment

Sequence of actions Registration of the problem solution
1. We write down the condition of the problem Given:

m (CaCl2) = 33.3 g


Find: m (Ca3 (PO4) 2) =?

2. Let’s calculate the molar masses for the formulas written in the given M (CaCl2) = 111 g / mol

M (Ca3 (PO4) 2) = 310 g / mol

3. Let’s calculate the amount of substances, the mass of which is given in the condition ν (CaCl2) = m / M = 33.3 g / 111 g / mol = 0.3 mol
4. Let’s write down UHR. Let’s arrange the coefficients.

Under the formulas, we write the stoichiometric ratios displayed by the reaction equation.

5. Let’s calculate the amount of substance, the mass of which needs to be found
6. Let’s calculate the required mass m (Ca3 (PO4) 2) = ν (Ca3 (PO4) 2 ∙ M (Ca3 (PO4) 2) = 0.1 mol ∙ 310 g / mol = 31 g
7. Let’s write down the answer Answer: m (Ca3 (PO4) 2) = 31 g
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