Two solutions were mixed: one weighing 130 g and with a mass fraction of salt of 6%, the second weighing 70 g and with a mass fraction of the same salt of 2%. The mass of salt contained in the resulting solution is equal to
Determine the masses of substances in each solution
by the formula m (substance) = ω * m (solution)
m (substance) 1 = 130 * 0.06 = 7.8 g
m (substance) 2 = 70 * 0.02 = 1.4 g
m (substance) 3 = 9.2g
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