# Under normal conditions, atmospheric pressure at the top of the mountain = 286 mm Hg. Art., and at its foot – 625 mm Hg. Art.

Under normal conditions, atmospheric pressure at the top of the mountain = 286 mm Hg. Art., and at its foot – 625 mm Hg. Art. Determine the absolute and relative height of the mountain.

1) 625 mm Hg. Art. – 286 mm Hg Art. = 339 mm Hg. Art. – the pressure difference between the foot and the top of the mountain
2) h = (P1 – P2): ΔР = 339 mm Hg. Art. : 1 mmHg Art. × 10 m = 3390 m – relative height of the mountain
3) 760 mm Hg. Art. – 286 mm Hg Art. = 474 mm Hg. Art. – the pressure difference between sea level and the top of the mountain
4) h = (P1 – P2): ΔР = 474 mm Hg. Art. : 1 mmHg Art. × 10 m = 4740 m – absolute height of the mountain
Answer: h abs. = 4740 m, h rel. = 3390 m.

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