# Using the rule of energy transfer from one trophic level to another, construct pyramids of biomass and abundance

**Using the rule of energy transfer from one trophic level to another, construct pyramids of biomass and abundance for the following food chain:**

**plants -> grasshopper -> frog -> already -> snake-eating hawk.**

**The biomass of all meadow plants is 40 thousand kg, one herbaceous shoot – 0.5 g (0.0005 kg), 1 grasshopper – 1 g, 1 frog – 10 g, 1 snake – 100 g, 1 hawk – 2 kg.**

Since it is known that 10% of energy and biomass is transferred to each subsequent level of the food chain, we will perform the necessary calculations. The total number of plants in the meadow is 40,000: 0.0005 = 80,000,000. (Only part of the total number of plants is used for nutrition.)

To produce 2 kg of products, 1 hawk needs to eat 20 kg of snakes, that is, 200 pieces, which should consume 200 kg of frogs, which numerically corresponds to 20,000 copies. The frogs, in turn, consume 2000 kg or 2 million grasshoppers, destroying 20,000 kg of meadow vegetation or 40 million plant shoots. Thus, the pyramids of abundance (1) and biomass (2) will look like this:

1 hawk

2 Kg

200 snakes

20 kg

20,000 frogs

200 kg

2,000,000 grasshoppers

2000 kg

40,000,000 plant shoots

20,000 kg