What is the angular diameter of Jupiter’s moon Io when observing it from a spacecraft located at a distance of 576,000 km from the satellite, if it is known that the linear dimensions of Io and the Moon are almost the same.
If we know the angular diameter of the Moon (32 ‘) and the distance to it 384000 km, then
32 ‘/ (576000/384000) = 21’
If we know the linear diameter of the Moon is 3474 km, then 3474/576000 = 0.0060313 rad = 0.3456 ° = 20.7 ‘
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