What is the minimum amount of memory (in KB) that must be reserved to store any 128 x 128 pixel bitmap, provided the image can use 256 different colors? In the answer, write down only an integer, you do not need to write a unit of measurement.
One pixel is encoded with 8 bits of memory.
Total 128 * 128 = 2 ^ 7 • 2 ^ 7 = 2 ^ 7 pixels.
Then the amount of memory occupied by the image is 2 ^ 14 * 8 = 2 ^ 17 bits = 2 ^ 14 bytes = 2 ^ 4 * KB = 16 KB.
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