CH4 + 4Cl2 = CCl4 + 4HCl
From the conditions of the job, V (CH4) = 112 l. We calculate the amount of methane substance:
n (CH4) = V (CH4) / Vm = 112 / 22.4 = 5 mol.
In the reaction equation, methane has a coefficient of 1, and hydrogen chloride has a coefficient of 4. Based on this:
n (HCl) = n (CH4) ⋅ 4/1 = 5 ⋅ 4/1 = 20 mol;
V (HCl) = n (HCl) ⋅ Vm = 20 ⋅ 22.4 = 448 l.
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