What is the volume of hydrogen released during the formation of 50 l of butadiene from butane? Gas volumes are measured under the same conditions.

C4H10 = C4H6 + 2H2
The number of moles of hydrogen = 2 * the number of moles of butane, and
hydrogen volume = 2 * butane volume, which means
hydrogen volume = 2 * 50 = 100 l

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