What mass of bromine is released when 0.3 mol of potassium bromide reacts with an excess of chlorine?

2 KBr + Cl2 = 2KCl + Br2
Determine the amount of bromine released by the reaction equation
0.3 / 2 = X / 1
X = 0.3 * 1/2 = 0.15 mol (Br2)
Find the mass of bromine m = M * n
n = 160 g / mol * 0.15 mol = 24 g.

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