What mass of nitrogen is formed during the combustion of 11.2 liters of ammonia?

2NH3 + 1.5O2 = N2 + 3H2O
the number of moles of nitrogen is 2 times less than the number of moles of ammonia, which means it is (11.2 / 22.4) / 2 = 0.25 mol. Its mass is 0.25 * 28 = 7 g.

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