What temperature does a star have if its maximum radiation falls on a wavelength of 4000 angstroms?
| September 15, 2020 | Education
Lambda (max) = b / T b = 0.0029 K × m Wine constant
Lambda = 4000 × 10 ^ -10 m
T = b / lambda = 0.0029 / 4000 × 10 ^ -10 = 7250K
Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.