2C2H2 + 5O2 = 4CO2 + 2H2O
n (C2H2) = V (C2H2) / Vm = 3 / 22.4 = 0.1339 mol
Before C2H2, coefficient 2, before CO2 – 4. Therefore, the amount of carbon dioxide through the amount of acetylene can be expressed as follows:
n (CO2) = n (C2H2) ⋅ 4/2 = 0.1339 ⋅ 4/2 = 0.2678 mol.
V (CO2) = n (CO2) ⋅ Vm = 0.2678 ⋅ 22.4 = 6 l.
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