What volume of gas is formed as a result of the interaction of carbon monoxide with 9 liters of oxygen?

Reaction equation:

2CO + O2 → 2CO2

We calculate the amount of oxygen substance:

n (O2) = V (O2) / Vm = 9 / 22.4 = 0.402 mol

O2 has a coefficient of 1, and CO2 has a coefficient of 2. Thus, the amount of CO2 substance in terms of the amount of O2 substance can be expressed as follows:

n (CO2) = n (O2) ⋅ 2/1 = 0.402 ⋅ 2 = 0.804 mol

Hence:

V (CO2) = n (CO2) ⋅ Vm = 0.804 ⋅ 22.4 = 18 L