# What volume of hydrogen sulfide is formed by the interaction of 880 g of technical iron (II) sulfide, containing 10% impurities

What volume of hydrogen sulfide is formed by the interaction of 880 g of technical iron (II) sulfide, containing 10% impurities, with a solution containing 10 mol of hydrochloric acid. 1) Let’s compose the reaction equation:
FeS + 2HCl = FeCl2 + H2S ↑
2) Calculate the mass and amount of the FeS substance:
ω (FeS) = 100 – ω (impurities) = 100-10 = 90%
m (FeS) = (m (solution)) ∙ ω (FeS) / 100% = 880 ∙ 90/100 = 792 g.
n (FeS) = m (FeS) / M (FeS) = 792/88 = 9 mol.
3) Determine the volume of released gas:
According to the reaction equation:
n (H2S) = n (FeS) = 2n (HCl)
FeS is in excess, HCl will react completely and 5 mol of H2S is formed
V (H2S) = n (H2S) ∙ Vm = 5 • 22.4 = 112 liters. Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.