2H2O2 = to => 2H2O + O2 ↑
From the conditions of the problem:
n (H2O2) = 4 mol,
In the reaction equation, oxygen has a coefficient of 1 (not in the equation), and hydrogen peroxide – 2. This means that the amount of oxygen substance in terms of the amount of hydrogen peroxide substance is expressed as follows:
n (O2) = n (H2O2) ⋅ 1/2 = 4 ⋅ 1/2 = 2 mol.
V (O2) = Vm ⋅ n (O2) = 22.4 ⋅ 2 = 44.8 l.
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