When aluminum was dissolved in an excess of alkali, 8.4 L of gas was released. The mass of the reacted aluminum is

bystudin | May 28, 2020 | Education

the number of moles of aluminum = (the number of moles of hydrogen) * 2 / (3 * 22.4) = 8.4 * 2 / (3 * 22.4) = 0.25 mol
aluminum mass = 0.25 * 27 = 6.75 g

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