When an electric current was flowing through the spiral of the lamp, the electric forces did the work of 100 J. At the same time

When an electric current was flowing through the spiral of the lamp, the electric forces did the work of 100 J. At the same time, 80 J was transferred to the environment due to thermal conductivity. Determine the energy released in the form of electromagnetic radiation, considering the internal energy of the lamp unchanged.

U = -Q + A = -80 + 100 = 20 J

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