When copper was dissolved in dilute nitric acid, 141 g of salt was obtained. The volume of nitric oxide (II) formed is

bystudin | May 28, 2020 | Education

3Cu + 8HNO3 = 3Cu (NO3) 2 + 2NO + 4H2O
2n (Cu (NO3) 2) = 3n (NO)
2m (Cu (NO3) 2) / M (Cu (NO3) 2) = 3V (NO) / 22.4
2 * 141/188 = 3V (NO) / 22.4
V (NO) = 2 * 141 * 22.4 / (3 * 188) = 11.2 L

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